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c++ Programming Glossary: e1Issue when scheduling tasks using clock() function http://stackoverflow.com/questions/11865460/issue-when-scheduling-tasks-using-clock-function public std less event bool operator const event e1 const event e2 const return e2.when_ e1.when_ std priority_queue.. const event e1 const event e2 const return e2.when_ e1.when_ std priority_queue event std vector event event_less..
http://stackoverflow.com/questions/1390703/enumerate-over-an-enum-in-c c template typename Enum bool operator enum_iterator Enum e1 enum_iterator Enum e2 return e1.get_enum e2.get_enum template.. enum_iterator Enum e1 enum_iterator Enum e2 return e1.get_enum e2.get_enum template typename Enum bool operator enum_iterator.. template typename Enum bool operator enum_iterator Enum e1 enum_iterator Enum e2 return e1 e2 share improve this answer..
Maintaining a unique set of elements on different criteria C++ STL http://stackoverflow.com/questions/4450095/maintaining-a-unique-set-of-elements-on-different-criteria-c-stl struct IDComparator bool operator const Employee e1 const Employee e2 return e1 id e2 id struct NameComparator.. bool operator const Employee e1 const Employee e2 return e1 id e2 id struct NameComparator bool operator const Employee.. e2 id struct NameComparator bool operator const Employee e1 const Employee e2 return e1 name e2 name struct AddressComparator..
How to emulate C array initialization “int arr[] = { e1, e2, e3, … }” behaviour with std::array? http://stackoverflow.com/questions/6114067/how-to-emulate-c-array-initialization-int-arr-e1-e2-e3-behaviou to emulate C array initialization &ldquo int arr e1 e2 e3 &hellip &rdquo behaviour with std array Note This question..
Uninitialized memory blocks in VC++ http://stackoverflow.com/questions/65724/uninitialized-memory-blocks-in-vc
Concatenating C++ iterator ranges into a const vector member variable at construction time http://stackoverflow.com/questions/757153/concatenating-c-iterator-ranges-into-a-const-vector-member-variable-at-constru typedef value_type reference concat_iterator T1 b1 T1 e1 T2 b2 T2 e2 seq1 b1 seq1end e1 seq2 b2 seq2end e2 iterator operator.. concat_iterator T1 b1 T1 e1 T2 b2 T2 e2 seq1 b1 seq1end e1 seq2 b2 seq2end e2 iterator operator if seq1 seq1end seq1 else.. T1 typename T2 concat_iterator T1 T2 concat_begin T1 b1 T1 e1 T2 b2 T2 e2 return concat_iterator T1 T2 b1 e1 b2 e2 template..
When does invoking a member function on a null instance result in undefined behavior? http://stackoverflow.com/questions/2474018/when-does-invoking-a-member-function-on-a-null-instance-result-in-undefined-beha the result is undefined. This follows from §5.2.5 3 If E1 has the type pointer to class X then the expression E1 E2 is.. If E1 has the type pointer to class X then the expression E1 E2 is converted to the equivalent form E1 .E2 E1 will result.. the expression E1 E2 is converted to the equivalent form E1 .E2 E1 will result in undefined behavior with a strict interpretation..
http://stackoverflow.com/questions/3784996/why-does-left-shift-operation-invoke-undefined-behaviour-when-the-left-side-oper value. Relevant quote from ISO C99 6.5.7 4 The result of E1 E2 is E1 left shifted E2 bit positions vacated bits are filled.. Relevant quote from ISO C99 6.5.7 4 The result of E1 E2 is E1 left shifted E2 bit positions vacated bits are filled with zeros... E2 bit positions vacated bits are filled with zeros. If E1 has an unsigned type the value of the result is E1 2 E2 reduced..
http://stackoverflow.com/questions/988158/take-the-address-of-a-one-past-the-end-array-element-via-subscript-legal-by-the says about array subscripting 5.2.1 1 The expression E1 E2 is identical by definition to E1 E2 Of course there's an obvious.. 5.2.1 1 The expression E1 E2 is identical by definition to E1 E2 Of course there's an obvious caveat Your example doesn't..
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