¡@
c++ Programming Glossary: mantissaExtended Precision Floating Point Library C/C++ http://stackoverflow.com/questions/10156002/extended-precision-floating-point-library-c-c initialization required for variables specify size of both mantissa and exponent C C interface support for really large floats 10^10000.. fixed with 15 bits . It allows me various choices for the mantissa but the largest representable number is always limited to 10^4932... for. It allows to specify big floats with exponent and mantissa value and it does not require initialization. share improve..
Why doesn't (int)0.9999999999999999999728949456878623891498136799780L == 0 (possible GCC bug)? http://stackoverflow.com/questions/16831464/why-doesnt-int0-9999999999999999999728949456878623891498136799780l-0-poss in x . With the assumed format for long double with 64 mantissa bits the highest representable number less than 1.0 is in hexadecimal..
What is the maximum length in chars needed to represent any double value? http://stackoverflow.com/questions/1701055/what-is-the-maximum-length-in-chars-needed-to-represent-any-double-value number of digits needed to represent the largest possible mantissa value otherwise there will also be a decimal point followed.. it needs enough digits to cover both the exponent and the mantissa. This value is pow 2 DBL_MIN_EXP DBL_MANT_DIG where DBL_MIN_EXP..
A fast method to round a double to a 32-bit int explained http://stackoverflow.com/questions/17035464/a-fast-method-to-round-a-double-to-a-32-bit-int-explained are doing in the end is just taking the lowest 32 bits of mantissa. Now to the magic number as you correctly stated 6755399441055744.. exactly the integers This follows from the fact that the mantissa is 52 bits wide. The other interesting fact about adding 2 51.. fact about adding 2 51 2 52 is that it affects the mantissa only in the two highest bits which are discarded anyway since..
Concept behind these four lines of tricky C++ code http://stackoverflow.com/questions/17992553/concept-behind-these-four-lines-of-tricky-c-code the position of the sign ^ of the exponent and of the mantissa i.e. the value without the exponent . Since the representation.. . Since the representation uses binary exponent and mantissa doubling the number increments the exponent by one. Your program..
biggest integer that can be stored in a double http://stackoverflow.com/questions/1848700/biggest-integer-that-can-be-stored-in-a-double losing precision. An IEEE 64 bit double has 52 bits of mantissa so I think it's 2^53 2^53 1 can't be stored because the 1 at.. 2^53 can be stored with 52 bits explicitly stored in the mantissa and then the exponent in effect giving you another one. 2^53..
how can I extract the mantissa of a double http://stackoverflow.com/questions/5672960/how-can-i-extract-the-mantissa-of-a-double can I extract the mantissa of a double I would like to store in a variable the mantisssa.. of a double click here What should I change to isolate the mantissa c double share improve this question In math.h double frexp.. frexp double value int exp decompose VALUE in exponent and mantissa. double ldexp double value int exp does the reverse. To get..
Optimizations for pow() with const non-integer exponent? http://stackoverflow.com/questions/6475373/optimizations-for-pow-with-const-non-integer-exponent exponents. Large exponents lead to high error because the mantissa bits are mingled with the exponent bits by the multiplication...
What exactly is a type cast in C/C++? http://stackoverflow.com/questions/7558837/what-exactly-is-a-type-cast-in-c-c of both are completely different complement on two mantissa . So what happens internally The example here is quite straightforward..
Fast multiplication/division by 2 for floats and doubles (C/C++) http://stackoverflow.com/questions/7720668/fast-multiplication-division-by-2-for-floats-and-doubles-c-c is a standard representation of doubles sign exponent mantissa is there a way to play with the exponent to get fast multiplications..
|