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jquery Programming Glossary: jquery.prototypeDifference of the value, prototype and property http://stackoverflow.com/questions/12143590/difference-of-the-value-prototype-and-property 'enhanced' return new jQuery.fn.init arg jQuery.fn jQuery.prototype constructor jQuery init function selector context rootjQuery.. methods jQuery.extend method function When initiates the jQuery.prototype.init initiates and returns an array of elements. But i could.. for those who don't use the fn property. Now you have jQuery.prototype jQuery.fn ¦]init.prototype But they also do two weird things..
How can you if check a jQuery plugin is already bound to a DOM node? http://stackoverflow.com/questions/13143745/how-can-you-if-check-a-jquery-plugin-is-already-bound-to-a-dom-node prototype because of this line from jquery.js jQuery.fn jQuery.prototype ... ... after .fn.extend was called to plug in that plugin no..
Why jQuery do this: jQuery.fn.init.prototype = jQuery.fn? http://stackoverflow.com/questions/1755080/why-jquery-do-this-jquery-fn-init-prototype-jquery-fn Little extended question is why jQuery do jQuery.fn jQuery.prototype init function ... f1 function ... ... jQuery.fn.init.prototype.. improve this question The jQuery.fn is just an alias for jQuery.prototype. I suppose it is defined for aesthetic and less typing reasons... reasons. So jQuery.fn.init.prototype jQuery.fn is actually jQuery.prototype.init.prototype jQuery.prototype As why this needs to be done..
Check if object is a jQuery object http://stackoverflow.com/questions/1853223/check-if-object-is-a-jquery-object of jQuery setting it's properties to those found on jQuery.prototype aka jQuery.fn . Thus you get a new object where instanceof jQuery.. where instanceof jQuery is true . 1 It's actually new jQuery.prototype.init foo the constructor logic has been offloaded to another..
Why is the init function in jQuery.prototype and not in jQuery's closure? http://stackoverflow.com/questions/18782973/why-is-the-init-function-in-jquery-prototype-and-not-in-jquerys-closure is the init function in jQuery.prototype and not in jQuery's closure Why is the init function in jQuery.prototype.. and not in jQuery's closure Why is the init function in jQuery.prototype I have put it in jQuery's closure and it works fine. I did this..
jquery - difference between $.functionName and $.fn.FunctionName http://stackoverflow.com/questions/2845981/jquery-difference-between-functionname-and-fn-functionname times before but I can't find the link. .fn points to the jQuery.prototype . Any methods or properties you add to it become available to..
Help understanding jQuery's jQuery.fn.init Why is init in fn http://stackoverflow.com/questions/4754560/help-understanding-jquerys-jquery-fn-init-why-is-init-in-fn defined as jQuery.fn.init which is another way to say jQuery.prototype.init which is the selector function What this means is that.. And remember the jQuery.fn is exactly the same as saying jQuery.prototype so really all that part is doing is assigning .init as a method..
Yepnope and “Proxy”-ing jQuery's ready() function http://stackoverflow.com/questions/5428717/yepnope-and-proxy-ing-jquerys-ready-function fn var jQuery _jQuery window.jQuery _ window. jQuery jQuery.prototype constructor jQuery ready function fn yepnope test window.jQuery.length..
http://stackoverflow.com/questions/7644199/jquery-source-code-questions selector context rootjQuery ... ... jQuery.fn jQuery.prototype constructor jQuery init function selector context rootjQuery..
How can jQuery behave like an object and a function? http://stackoverflow.com/questions/8734115/how-can-jquery-behave-like-an-object-and-a-function this means that every instance of inherits methods from jQuery.prototype . See Notes A very rough demo to achieve the similar behaviour.. is a shorthand for defining jQuery plugins . jQuery.fn jQuery.prototype constructor jQuery init function ..parameters.. .... sets default..
Difference of the value, prototype and property http://stackoverflow.com/questions/12143590/difference-of-the-value-prototype-and-property arg The jQuery object is actually just the init constructor 'enhanced' return new jQuery.fn.init arg jQuery.fn jQuery.prototype constructor jQuery init function selector context rootjQuery get the selected DOM el. and returns an array method function.. method extends the jQuery function and adds some static methods jQuery.extend method function When initiates the jQuery.prototype.init initiates and returns an array of elements. But i could not understand how it adds the jQuery method like .css or .hide.. set the prototype property of the jQuery function to that object for those who don't use the fn property. Now you have jQuery.prototype jQuery.fn ¦]init.prototype But they also do two weird things overwriting the constructor property of the prototype object..
How can you if check a jQuery plugin is already bound to a DOM node? http://stackoverflow.com/questions/13143745/how-can-you-if-check-a-jquery-plugin-is-already-bound-to-a-dom-node jQuery wrapped collection of elements has this method in its prototype because of this line from jquery.js jQuery.fn jQuery.prototype ... ... after .fn.extend was called to plug in that plugin no pun intended. But even if my plugin were required to change..
Why jQuery do this: jQuery.fn.init.prototype = jQuery.fn? http://stackoverflow.com/questions/1755080/why-jquery-do-this-jquery-fn-init-prototype-jquery-fn jQuery do this jQuery.fn.init.prototype jQuery.fn Little extended question is why jQuery do jQuery.fn jQuery.prototype init function ... f1 function ... ... jQuery.fn.init.prototype jQuery.fn Why not simply add f1 etc into init.prototype Is.. or there are some deep ideas javascript jquery share improve this question The jQuery.fn is just an alias for jQuery.prototype. I suppose it is defined for aesthetic and less typing reasons. So jQuery.fn.init.prototype jQuery.fn is actually jQuery.prototype.init.prototype.. I suppose it is defined for aesthetic and less typing reasons. So jQuery.fn.init.prototype jQuery.fn is actually jQuery.prototype.init.prototype jQuery.prototype As why this needs to be done this forum post is helpful It gives the init function the same..
Check if object is a jQuery object http://stackoverflow.com/questions/1853223/check-if-object-is-a-jquery-object this inside the constructor function to point to a new instance of jQuery setting it's properties to those found on jQuery.prototype aka jQuery.fn . Thus you get a new object where instanceof jQuery is true . 1 It's actually new jQuery.prototype.init foo.. on jQuery.prototype aka jQuery.fn . Thus you get a new object where instanceof jQuery is true . 1 It's actually new jQuery.prototype.init foo the constructor logic has been offloaded to another constructor function called init but the concept is the same...
Why is the init function in jQuery.prototype and not in jQuery's closure? http://stackoverflow.com/questions/18782973/why-is-the-init-function-in-jquery-prototype-and-not-in-jquerys-closure is the init function in jQuery.prototype and not in jQuery's closure Why is the init function in jQuery.prototype I have put it in jQuery's closure and it works.. is the init function in jQuery.prototype and not in jQuery's closure Why is the init function in jQuery.prototype I have put it in jQuery's closure and it works fine. I did this function window undefined var jQuery function selector context..
jquery - difference between $.functionName and $.fn.FunctionName http://stackoverflow.com/questions/2845981/jquery-difference-between-functionname-and-fn-functionname question I'm sure this question has been asked several times before but I can't find the link. .fn points to the jQuery.prototype . Any methods or properties you add to it become available to all instance of the jQuery wrapped objects. .something adds..
Help understanding jQuery's jQuery.fn.init Why is init in fn http://stackoverflow.com/questions/4754560/help-understanding-jquerys-jquery-fn-init-why-is-init-in-fn so I'm leaving it. What is going on is that jQuery is being defined as jQuery.fn.init which is another way to say jQuery.prototype.init which is the selector function What this means is that no one would call jQuery.fn.init or jQuery.init because jQuery.. it's a verbose version of jQuery 'div' after that assignment. And remember the jQuery.fn is exactly the same as saying jQuery.prototype so really all that part is doing is assigning .init as a method of the prototype of the jQuery object. I.E. a jQuery plugin...
Yepnope and “Proxy”-ing jQuery's ready() function http://stackoverflow.com/questions/5428717/yepnope-and-proxy-ing-jquerys-ready-function 'function' yepnope test window.jQuery.length complete function fn var jQuery _jQuery window.jQuery _ window. jQuery jQuery.prototype constructor jQuery ready function fn yepnope test window.jQuery.length complete function fn return jQuery window.jQuery..
http://stackoverflow.com/questions/7644199/jquery-source-code-questions actually just the init constructor 'enhanced' return new jQuery.fn.init selector context rootjQuery ... ... jQuery.fn jQuery.prototype constructor jQuery init function selector context rootjQuery var match elem ret doc Thank you jquery share improve this..
How can jQuery behave like an object and a function? http://stackoverflow.com/questions/8734115/how-can-jquery-behave-like-an-object-and-a-function an Object. JavaScript is a prototypical language. For jQuery this means that every instance of inherits methods from jQuery.prototype . See Notes A very rough demo to achieve the similar behaviour function Closure to not leak local variables to the global.. new jQuery.fn.init selector context rootjQuery .fn jQuery.fn is a shorthand for defining jQuery plugins . jQuery.fn jQuery.prototype constructor jQuery init function ..parameters.. .... sets default properties... ....other methods such as size get etc.....
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