¡@

Home 

php Programming Glossary: evaluated

Parse error: syntax error, unexpected '(', expecting ',' or ';' in

http://stackoverflow.com/questions/11313051/parse-error-syntax-error-unexpected-expecting-or-in

must be a constant value that is it must be able to be evaluated at compile time and must not depend on run time information.. and must not depend on run time information in order to be evaluated. The workaround is to set your variable in the constructor private..

PHP file cannot enter some part of code

http://stackoverflow.com/questions/11575531/php-file-cannot-enter-some-part-of-code

The return value will be casted to boolean and then evaluated. Returns true on success or false on failure. public function..

PDO: bindParam versus bindValue

http://stackoverflow.com/questions/1179874/pdo-bindparam-versus-bindvalue

the variable is bound as a reference and will only be evaluated at the time that PDOStatement execute is called. And execute..

PHP mysql insert date format

http://stackoverflow.com/questions/12120433/php-mysql-insert-date-format

you pass your variables as parameters that do not get evaluated for SQL. If you don't know what I'm talking about or how to..

Reference: Why does the PHP (or other server side) code in my Javascript not work?

http://stackoverflow.com/questions/13840429/reference-why-does-the-php-or-other-server-side-code-in-my-javascript-not-wor

Javascript code is now sent to the client where it gets evaluated. The alert call works while the foo variable is not used anywhere...

PHP Type-Juggling and (strict) Greater/Lesser Than Comparisons

http://stackoverflow.com/questions/15813490/php-type-juggling-and-strict-greater-lesser-than-comparisons

that this is true only as of PHP 5.4 . Previously INF INF evaluated to true . PHP's operator is not asymmetric i.e. from a b does..

declare property as object?

http://stackoverflow.com/questions/2202995/declare-property-as-object

must be a constant value that is it must be able to be evaluated at compile time and must not depend on run time information.. and must not depend on run time information in order to be evaluated. Either create it inside the constructor composition class Foo..

Initializing PHP class property declarations with simple expressions yields syntax error

http://stackoverflow.com/questions/2702863/initializing-php-class-property-declarations-with-simple-expressions-yields-synt

must be a constant value that is it must be able to be evaluated at compile time and must not depend on run time information.. and must not depend on run time information in order to be evaluated. I'm trying to initialize an array and having some issues. While.. be optimized away. In any case it's certainly able to be evaluated at compile time. So what's going on here Is the limitation really..

What is the difference between single-quoted and double-quoted strings in PHP?

http://stackoverflow.com/questions/3446216/what-is-the-difference-between-single-quoted-and-double-quoted-strings-in-php

some regexes and variables in the strings will be evaluated. An important point here is that you can use curly braces to.. curly braces to isolate the name of the variable you want evaluated . For example let's say you have the variable type and you what..

Why don't PHP attributes allow functions?

http://stackoverflow.com/questions/3960323/why-dont-php-attributes-allow-functions

values are also static scalars static_scalar compile time evaluated scalars ... T_ARRAY ' ' static_array_pair_list ' ' ... ... Let's..

Reference: Comparing PHP's print and echo

http://stackoverflow.com/questions/7094118/reference-comparing-phps-print-and-echo

that is the arguments are passed to them without being evaluated which requires special treatment from the compiler. print happens.. only have to define the semantics for print . print e when evaluated evaluates its single argument e and type casts the resulting..

Why is $a + ++$a == 2?

http://stackoverflow.com/questions/9709818/why-is-a-a-2

determine if the left or right operand of the operator is evaluated first. If the left operand is evaluated first the result would.. of the operator is evaluated first. If the left operand is evaluated first the result would be 0 1 and if the right operand is evaluated.. first the result would be 0 1 and if the right operand is evaluated first the result would be 1 1. Operator associativity also does..