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php Programming Glossary: u.id

Server Side PHP Long polling

http://stackoverflow.com/questions/12428587/server-side-php-long-polling

ON d.streamitem_id c.comment_streamitem JOIN users AS u ON u.id c.comment_poster WHERE c.comment_poster ' following_string'..

mySQL “Rank in Highscore”-Query

http://stackoverflow.com/questions/2118511/mysql-rank-in-highscore-query

AS sum_points FROM user u LEFT JOIN points p ON p.user_id u.id GROUP BY u.id ORDER BY sum_points DESC resulting in a fine highscore.. FROM user u LEFT JOIN points p ON p.user_id u.id GROUP BY u.id ORDER BY sum_points DESC resulting in a fine highscore list.. AS sum_points FROM user u LEFT JOIN points p ON p.user_id u.id GROUP BY u.id x just count the ones with higher sum_points where..

SQL Builder for PHP, with JOIN support?

http://stackoverflow.com/questions/216138/sql-builder-for-php-with-join-support

u' leftJoin 'u.Group g' innerJoin 'u.Phonenumber p WITH u.id 3' leftJoin 'u.Email e' users q execute And with Propel c new..

MySQL User defined variable within Doctrine and Symfony

http://stackoverflow.com/questions/6541999/mysql-user-defined-variable-within-doctrine-and-symfony

which works fine. query this createQuery 'r' select 'u.id CONCAT u.first_name LEFT u.last_name 1 as full_name u.first_name.. you can do this SET @rank 0 SELECT @rank @rank 1 as rank u.id u.first_name ....etc So my question is how can I get this to.. you could try query this createQuery 'r' select 'COUNT u.id as rank u.id CONCAT u.first_name LEFT u.last_name 1 as full_name..

How do one use ACL to filter a list of domain-objects according to a certain user's permissions (e.g. EDIT)?

http://stackoverflow.com/questions/6621220/how-do-one-use-acl-to-filter-a-list-of-domain-objects-according-to-a-certain-use

for the object or objects . I.e WHERE other conditions AND u.id IN list of legal object ids here 2 A post query filter that..