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python Programming Glossary: aaa2

How do I ensure that re.findall() stops at the right place?

http://stackoverflow.com/questions/17765805/how-do-i-ensure-that-re-findall-stops-at-the-right-place

place Here is the code I have a ' title aaa title title aaa2 title title aaa3 title ' import re re.findall r' title . title.. title . title ' a The result is 'title' 'aaa title title aaa2 title title aaa3' ' title' If I ever designed a crawler to get.. if you only want one match s ' title aaa title title aaa2 title title aaa3 title ' import re re.search ' title . title..

every possible permutation of a string or combination including repeated character use java

http://stackoverflow.com/questions/5113707/every-possible-permutation-of-a-string-or-combination-including-repeated-charact

in order. That is the output will be aaaa aaab aaac aaa1 aaa2 aaa3 aaba aabb aabc aab1 ... 3323 333a 333b 333c 3331 3332 3333..

ANTLR get and split lexer content

http://stackoverflow.com/questions/5929797/antlr-get-and-split-lexer-content

print_level_order child indent 1 input ' aaa1 bbb ccc aaa2 ' char_stream antlr3.ANTLRStringStream input lexer CommentLexer.. tree 0 As you can see from the source aaa1 bbb ccc aaa2 the following AST is created COMMENT aaa1 COMMENT bbb COMMENT.. AST is created COMMENT aaa1 COMMENT bbb COMMENT ccc aaa2 EDIT II I mind as well show how you can invoke the Comment parser..