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python Programming Glossary: list_http://stackoverflow.com/questions/19990861/checking-for-sublist-in-list size of the sublist and comparing equality def n_slices n list_ for i in xrange len list_ 1 n yield list_ i i n def isSublist.. equality def n_slices n list_ for i in xrange len list_ 1 n yield list_ i i n def isSublist list_ sub_list for slice_.. def n_slices n list_ for i in xrange len list_ 1 n yield list_ i i n def isSublist list_ sub_list for slice_ in n_slices len..
Python: sort function breaks in the presence of nan http://stackoverflow.com/questions/4240050/python-sort-function-breaks-in-the-presence-of-nan nan . Anyway I ended up following @khachik's answer sorted list_ key lambda x float ' inf' if math.isnan x else x I suspect it..
Python wont remove items from list http://stackoverflow.com/questions/4301634/python-wont-remove-items-from-list into the problem first. Don't do things like for item in list_ list_.remove item because bad and confusing things happen. list_.. the problem first. Don't do things like for item in list_ list_.remove item because bad and confusing things happen. list_ range.. list_.remove item because bad and confusing things happen. list_ range 10 for item in list_ ... list_.remove item ... list_ 1..
Checking for NaN presence in a container http://stackoverflow.com/questions/9904699/checking-for-nan-presence-in-a-container NaN float 'nan' print NaN NaN # True print NaN NaN # False list_ 1 2 NaN print NaN in list_ # True works fine but how set_ 1.. # True print NaN NaN # False list_ 1 2 NaN print NaN in list_ # True works fine but how set_ 1 2 NaN print NaN in set_ # True..
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