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python Programming Glossary: root.findallParsing XML with namespace in Python ElementTree http://stackoverflow.com/questions/14853243/parsing-xml-with-namespace-in-python-elementtree following code tree ET.parse filename root tree.getroot root.findall 'owl Class' Because of the namespace I am getting the following.. 'owl' 'http www.w3.org 2002 07 owl#' # add more as needed root.findall 'owl Class' namespaces namespaces Prefixes are only looked up.. You can use the same syntax yourself too of course root.findall ' http www.w3.org 2002 07 owl# Class' If you can switch to the..
python: xml.etree.ElementTree, removing “namespaces” http://stackoverflow.com/questions/1703882/python-xml-etree-elementtree-removing-namespaces specifying the namespace is it possible For example root.findall molpro job instead of root.findall http www.molpro.net schema.. it possible For example root.findall molpro job instead of root.findall http www.molpro.net schema molpro2006 molpro http www.molpro.net.. with lxml2 it's possible to reduce this overhead somewhat root.findall n molpro n job namespaces dict n http www.molpro.net schema..
ElementTree XPath - Select Element based on attribute http://stackoverflow.com/questions/222375/elementtree-xpath-select-element-based-on-attribute def parse document root et.parse document for target in root.findall target @name 'a' print target._children I am receiving the following..
How to keep comments while parsing XML using Python / ElementTree http://stackoverflow.com/questions/4474754/how-to-keep-comments-while-parsing-xml-using-python-elementtree try doc Etree.parse file root doc.getroot for element in root.findall '. StateManageable' element.attrib 'initialState' state #end..
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