c++ Programming Glossary: addressable

http://stackoverflow.com/questions/1256246/address-of-register-variable

simply as an auto declaration. However whether or not addressable storage is actually used the address of any part of an object..

One-byte bool. Why?

http://stackoverflow.com/questions/14220726/one-byte-bool-why

is enough Because every object in C must be individually addressable that is you must be able to have a pointer to it . You cannot..

Porting 32 bit C++ code to 64 bit - is it worth it? Why?

http://stackoverflow.com/questions/1479953/porting-32-bit-c-code-to-64-bit-is-it-worth-it-why

of some the obvious gains of the x64 architecture higher addressable RAM addresses etc ... but What if my program has no real need..

What does this C++ code mean?

http://stackoverflow.com/questions/1604968/what-does-this-c-code-mean

is implementation defined. Bit fields are packed into some addressable allocation unit. Note bit fields straddle allocation units on..

C++ : why bool is 8 bits long?

http://stackoverflow.com/questions/2064550/c-why-bool-is-8-bits-long

improve this question Because every C data type must be addressable. How would you create a pointer to a single bit You can't. But.. to the implementation. The main thing is that it must be addressable so no C datatype can be smaller than a byte share improve..

Why is a char and a bool the same size in c++?

http://stackoverflow.com/questions/266870/why-is-a-char-and-a-bool-the-same-size-in-c

In modern computer architectures a byte is the smallest addressable unit of memory. To pack multiple bits into a byte requires applying..

Why are references not reseatable in C++

http://stackoverflow.com/questions/728233/why-are-references-not-reseatable-in-c

a function is called. Since references are not directly addressable for example references have no address returns the address of..

How a bool type variable is stored in memory? (C++)

http://stackoverflow.com/questions/7967924/how-a-bool-type-variable-is-stored-in-memory-c

test 1 if using VS 2010. Since every C data type must be addressable the test bool variable is 8 bits 1 byte . My question is that.. improve this question Every element of test1 must be addressable. This implies that test1 takes at least 32 bytes and not bits..

Why is it illegal to take the address of an rvalue temporary?

http://stackoverflow.com/questions/8763398/why-is-it-illegal-to-take-the-address-of-an-rvalue-temporary

in the sense that the temporary may not be stored in addressable memory. In fact very often functions compiled for RISC architectures.. their values on the stack. Therefore they're stored in addressable memory and have a valid address. share improve this answer..