c++ Programming Glossary: interpretationSet all bytes of int to (unsigned char)0, guaranteed to represent zero? http://stackoverflow.com/questions/11138188/set-all-bytes-of-int-to-unsigned-char0-guaranteed-to-represent-zero wrong bit pattern in them may imply a not valid value. the interpretation is a pure binary representation something whose definition is..
How can I use C++ code to interact with PHP? http://stackoverflow.com/questions/1502244/how-can-i-use-c-code-to-interact-with-php to do some things faster if programmed well no need for interpretation of PHP code only execution of machine code which is generally..
Understanding stack frame of function call in C/C++? [closed] http://stackoverflow.com/questions/16088040/understanding-stack-frame-of-function-call-in-c-c specific hardware support Think about the execution or interpretation of a recursively defined function like the good old factorial..
Explicit Type Conversion and Multiple Simple Type Specifiers http://stackoverflow.com/questions/2144012/explicit-type-conversion-and-multiple-simple-type-specifiers Kr羹gler of the C standards committee agreed with the interpretation that unsigned int is a combination of simple type specifiers..
C++ typedef interpretation of const pointers http://stackoverflow.com/questions/2253738/c-typedef-interpretation-of-const-pointers typedef interpretation of const pointers Firstly sample codes Case 1 typedef char..
Should operator<< be implemented as a friend or as a member function? http://stackoverflow.com/questions/236801/should-operator-be-implemented-as-a-friend-or-as-a-member-function share improve this question The problem here is in your interpretation of the article you link . This article is about somebody that..
When does invoking a member function on a null instance result in undefined behavior? http://stackoverflow.com/questions/2474018/when-does-invoking-a-member-function-on-a-null-instance-result-in-undefined-beha E1 .E2 E1 will result in undefined behavior with a strict interpretation and .E2 converts it to an rvalue making it undefined behavior.. it to an rvalue making it undefined behavior for the weak interpretation. It also follows that it's undefined behavior directly from.. is undefined. With static functions the strict versus weak interpretation makes the difference. Strictly speaking it is undefined A static..
References Needed for Implementing an Interpreter in C/C++ http://stackoverflow.com/questions/294852/references-needed-for-implementing-an-interpreter-in-c-c LISP target compilation for faster execution. For faster interpretation I would take a look at the most recent JavaScript interpreters..
Value initialization and Non POD types http://stackoverflow.com/questions/3931312/value-initialization-and-non-pod-types fields according to last point . So where am I wrong Is my interpretation of value initialization correct c visual c initialization value..
constructor invocation mechanism http://stackoverflow.com/questions/4283576/constructor-invocation-mechanism now interpret it as an expression because of the extra My interpretation my n my is equivalent to my n my . Now the rvalue expression..
Use of typename keyword with typedef and new http://stackoverflow.com/questions/4421306/use-of-typename-keyword-with-typedef-and-new when it then encounters the typedef . Inside classes the interpretation is slightly different but much like this too. That's a simple..
Is there a difference between foo(void) and foo() in C++ or C http://stackoverflow.com/questions/51032/is-there-a-difference-between-foovoid-and-foo-in-c-or-c this question The main reason is to achieve consistent interpretation of headers that are shared between C and C . In C void foo means.. By writing foo void therefore we achieve the same interpretation across both languages and make our headers multilingual though..
http://stackoverflow.com/questions/556255/how-to-throw-good-exceptions in a useful way . And I mean this in the widest possible interpretation a service that gives up will try again later a UI that provides..
Why is std::for_each a non-modifying sequence operation? http://stackoverflow.com/questions/662845/why-is-stdfor-each-a-non-modifying-sequence-operation v.end foo v now contains 12 I suspect this to be just an interpretation issue but I wanted to have your opinion about that. PS I know..
May I treat a 2D array as a contiguous 1D array? http://stackoverflow.com/questions/7269099/may-i-treat-a-2d-array-as-a-contiguous-1d-array behavior share improve this question It's up to interpretation. While the contiguity requirements of arrays don't leave much..
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