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c++ Programming Glossary: a.bSerializing and deserializing json with boost http://stackoverflow.com/questions/12394472/serializing-and-deserializing-json-with-boost tree interprets the keys as paths e.g. putting the pair a.b z will create an a b z JSON not an a.b z . Otherwise using property.. putting the pair a.b z will create an a b z JSON not an a.b z . Otherwise using property tree is trivial. Here is a little..
http://stackoverflow.com/questions/1604968/what-does-this-c-code-mean enum BOOL FALSE 0 TRUE 1 struct A BOOL b 1 A a void f a.b TRUE if a.b TRUE yields true ... end example share improve.. FALSE 0 TRUE 1 struct A BOOL b 1 A a void f a.b TRUE if a.b TRUE yields true ... end example share improve this answer..
When do I use a dot, arrow, or double colon to refer to members of a class in C++? http://stackoverflow.com/questions/4984600/when-do-i-use-a-dot-arrow-or-double-colon-to-refer-to-members-of-a-class-in-c that C has three ways to refer to members of a class a b a.b and a b . When do I use which one of these operators Note This.. know quite a lot about a and b just by looking at a b a.b or a b respectively in any code you look at. a b is only used.. case a will always be the name of a class or namespace . a.b is only used if b is a member of the object or reference to..
Why does C++ need the scope resolution operator? http://stackoverflow.com/questions/9338217/why-does-c-need-the-scope-resolution-operator situation I can think it would is so that something like a.b c would be parsed as a. b c but I can't think of any situation.. like this would be legal anyway. Who said syntax like a.b c is not legal Consider these classes struct A void f std cout..
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