c++ Programming Glossary: bar1

Operator & and * at function prototype in class

http://stackoverflow.com/questions/3065836/operator-and-at-function-prototype-in-class

So if I have that class I can do this ball.checkCollision bar1 But if I change the class to this class Sprite ... bool checkCollision.. Sprite spr ... I have to do this ball.checkCollision bar1 So what's the difference It's better a way instead other Thank.. In both cases you are actually passing the address of bar1 and you're not copying the value since both pointers Sprite..

How to enable_shared_from_this of both parend and derived

http://stackoverflow.com/questions/657155/how-to-enable-shared-from-this-of-both-parend-and-derived

bind foo foo_do_it shared_from_this virtual ~foo class bar1 public foo public enable_shared_from_this bar1 using enable_shared_from_this.. ~foo class bar1 public foo public enable_shared_from_this bar1 using enable_shared_from_this bar1 shared_from_this void bar1_do_it.. enable_shared_from_this bar1 using enable_shared_from_this bar1 shared_from_this void bar1_do_it cout foo do_it n public virtual..