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c++ Programming Glossary: getfooWhat does the explicit keyword in C++ mean? http://stackoverflow.com/questions/121162/what-does-the-explicit-keyword-in-c-mean used as an implicit conversion Foo int foo m_foo foo int GetFoo return m_foo private int m_foo Here's a simple function that.. that takes a Foo object void DoBar Foo foo int i foo.GetFoo and here's where the DoBar function is called. int main DoBar..
Passing a modifiable parameter to c++ function http://stackoverflow.com/questions/1322517/passing-a-modifiable-parameter-to-c-function to pass it by pointer or to pass it by reference bool GetFoo Foo whereToPlaceResult bool GetFoo Foo whereToPlaceResult I.. it by reference bool GetFoo Foo whereToPlaceResult bool GetFoo Foo whereToPlaceResult I am asking this because I always considered..
Returning object from function http://stackoverflow.com/questions/2616107/returning-object-from-function be modified during its lifetime. Thus const Foo SomeClass GetFoo return Foo invoked as someMethod const Foo l_Foo someClassPInstance.. invoked as someMethod const Foo l_Foo someClassPInstance GetFoo ... Scneraio B The returned object is to be stored in a variable.. will be modified during its lifetime. Thus void SomeClass GetFoo Foo a_Foo_ref a_Foo_ref Foo invoked as someMethod Foo l_Foo..
C++11 auto: what if it gets a constant reference? http://stackoverflow.com/questions/7138588/c11-auto-what-if-it-gets-a-constant-reference operator const Foo return this static Foo g_temp const Foo GetFoo return g_temp I tried to use auto like this auto my_foo GetFoo.. return g_temp I tried to use auto like this auto my_foo GetFoo I expected that my_foo will be a constant reference to Foo which.. to Foo I needed to write like this const auto my_foo2 GetFoo auto my_foo3 GetFoo Question Why does auto deduce the return..
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